4313404212133 has 4 divisors (see below), whose sum is σ = 4500943525728. Its totient is φ = 4125864898540.

The previous prime is 4313404212127. The next prime is 4313404212157. The reversal of 4313404212133 is 3312124043134.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4313404212133 - 2²¹ = 4313402114981 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4313404212095 and 4313404212104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4313404512133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93769656763 + ... + 93769656808.

It is an arithmetic number, because the mean of its divisors is an integer number (1125235881432).

Almost surely, 2^{4313404212133} is an apocalyptic number.

It is an amenable number.

4313404212133 is a deficient number, since it is larger than the sum of its proper divisors (187539313595).

4313404212133 is a wasteful number, since it uses less digits than its factorization.

4313404212133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 187539313594.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 4313404212133 its reverse (3312124043134), we get a palindrome (7625528255267).

The spelling of 4313404212133 in words is "four trillion, three hundred thirteen billion, four hundred four million, two hundred twelve thousand, one hundred thirty-three".