Base | Representation |
---|---|
bin | 110001000010011100010111… |
… | …0001011111010011010010111 |
3 | 2002120021010010201121122100121 |
4 | 1202010320232023322122113 |
5 | 423014121202121141210 |
6 | 4125220504314452411 |
7 | 156566412602312500 |
oct | 14204705613723227 |
9 | 2076233121548317 |
10 | 431344340412055 |
11 | 115492120047784 |
12 | 4046550aa34107 |
13 | 1568b79b135435 |
14 | 787326ad93ba7 |
15 | 34d03c98cc6da |
hex | 1884e2e2fa697 |
431344340412055 has 12 divisors (see below), whose sum is σ = 602121487432680. Its totient is φ = 295778976282384.
The previous prime is 431344340412053. The next prime is 431344340412061. The reversal of 431344340412055 is 550214043443134.
It is not a de Polignac number, because 431344340412055 - 21 = 431344340412053 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (431344340412053) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 880294572025 + ... + 880294572514.
It is an arithmetic number, because the mean of its divisors is an integer number (50176790619390).
Almost surely, 2431344340412055 is an apocalyptic number.
431344340412055 is a deficient number, since it is larger than the sum of its proper divisors (170777147020625).
431344340412055 is a wasteful number, since it uses less digits than its factorization.
431344340412055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1760589144558 (or 1760589144551 counting only the distinct ones).
The product of its (nonzero) digits is 1382400, while the sum is 43.
Adding to 431344340412055 its reverse (550214043443134), we get a palindrome (981558383855189).
The spelling of 431344340412055 in words is "four hundred thirty-one trillion, three hundred forty-four billion, three hundred forty million, four hundred twelve thousand, fifty-five".
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