Base | Representation |
---|---|
bin | 111110110001011111000… |
… | …100010001010010000111 |
3 | 120021101112002211202111022 |
4 | 332301133010101102013 |
5 | 1031134020440320241 |
6 | 13101412240301355 |
7 | 623441360012456 |
oct | 76613704212207 |
9 | 16241462752438 |
10 | 4313742120071 |
11 | 14134a1a7109a |
12 | 59804761185b |
13 | 253a26994c27 |
14 | 10cb015cab9d |
15 | 77324d0d54b |
hex | 3ec5f111487 |
4313742120071 has 4 divisors (see below), whose sum is σ = 4355623111632. Its totient is φ = 4271861128512.
The previous prime is 4313742120019. The next prime is 4313742120073. The reversal of 4313742120071 is 1700212473134.
4313742120071 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4313742120071 - 226 = 4313675011207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4313742120073) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20940495626 + ... + 20940495831.
It is an arithmetic number, because the mean of its divisors is an integer number (1088905777908).
Almost surely, 24313742120071 is an apocalyptic number.
4313742120071 is a deficient number, since it is larger than the sum of its proper divisors (41880991561).
4313742120071 is a wasteful number, since it uses less digits than its factorization.
4313742120071 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 41880991560.
The product of its (nonzero) digits is 28224, while the sum is 35.
The spelling of 4313742120071 in words is "four trillion, three hundred thirteen billion, seven hundred forty-two million, one hundred twenty thousand, seventy-one".
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