43140403433 has 4 divisors (see below), whose sum is σ = 43143162240. Its totient is φ = 43137644628.

The previous prime is 43140403429. The next prime is 43140403457. The reversal of 43140403433 is 33430404134.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33430404134 = 2 ⋅16715202067.

It is a cyclic number.

It is not a de Polignac number, because 43140403433 - 2² = 43140403429 is a prime.

It is a super-2 number, since 2×43140403433² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 43140403396 and 43140403405.

It is not an unprimeable number, because it can be changed into a prime (43140403633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1355813 + ... + 1387266.

It is an arithmetic number, because the mean of its divisors is an integer number (10785790560).

Almost surely, 2^43140403433 is an apocalyptic number.

It is an amenable number.

43140403433 is a deficient number, since it is larger than the sum of its proper divisors (2758807).

43140403433 is a wasteful number, since it uses less digits than its factorization.

43140403433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2758806.

The product of its (nonzero) digits is 20736, while the sum is 29.

Adding to 43140403433 its reverse (33430404134), we get a palindrome (76570807567).

The spelling of 43140403433 in words is "forty-three billion, one hundred forty million, four hundred three thousand, four hundred thirty-three".