Base | Representation |
---|---|
bin | 111110110001110110011… |
… | …000101101101011101101 |
3 | 120021102112101000120020221 |
4 | 332301312120231223231 |
5 | 1031140321114331440 |
6 | 13101515134011341 |
7 | 623454150321010 |
oct | 76616630555355 |
9 | 16242471016227 |
10 | 4314133355245 |
11 | 141368289a94a |
12 | 598136646b51 |
13 | 253a89a57c2c |
14 | 10cb3b54d377 |
15 | 7734933ed4a |
hex | 3ec7662daed |
4314133355245 has 16 divisors (see below), whose sum is σ = 5933006334720. Its totient is φ = 2950022577024.
The previous prime is 4314133355173. The next prime is 4314133355249. The reversal of 4314133355245 is 5425533314134.
It is a cyclic number.
It is not a de Polignac number, because 4314133355245 - 29 = 4314133354733 is a prime.
It is a super-2 number, since 2×43141333552452 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4314133355249) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 171660072 + ... + 171685201.
It is an arithmetic number, because the mean of its divisors is an integer number (370812895920).
Almost surely, 24314133355245 is an apocalyptic number.
It is an amenable number.
4314133355245 is a deficient number, since it is larger than the sum of its proper divisors (1618872979475).
4314133355245 is a wasteful number, since it uses less digits than its factorization.
4314133355245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 343345644.
The product of its digits is 1296000, while the sum is 43.
Adding to 4314133355245 its reverse (5425533314134), we get a palindrome (9739666669379).
The spelling of 4314133355245 in words is "four trillion, three hundred fourteen billion, one hundred thirty-three million, three hundred fifty-five thousand, two hundred forty-five".
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