43143413521253 has 4 divisors (see below), whose sum is σ = 43143477260268. Its totient is φ = 43143349782240.

The previous prime is 43143413521223. The next prime is 43143413521303. The reversal of 43143413521253 is 35212531434134.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7581250107649 + 35562163413604 = 2753407^2 + 5963402^2 .

It is a cyclic number.

It is not a de Polignac number, because 43143413521253 - 2²⁶ = 43143346412389 is a prime.

It is a super-3 number, since 3×43143413521253³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 43143413521253.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43143413521223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30843176 + ... + 32211617.

It is an arithmetic number, because the mean of its divisors is an integer number (10785869315067).

Almost surely, 2^{43143413521253} is an apocalyptic number.

It is an amenable number.

43143413521253 is a deficient number, since it is larger than the sum of its proper divisors (63739015).

43143413521253 is an equidigital number, since it uses as much as digits as its factorization.

43143413521253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63739014.

The product of its digits is 518400, while the sum is 41.

Adding to 43143413521253 its reverse (35212531434134), we get a palindrome (78355944955387).

The spelling of 43143413521253 in words is "forty-three trillion, one hundred forty-three billion, four hundred thirteen million, five hundred twenty-one thousand, two hundred fifty-three".