Base | Representation |
---|---|
bin | 111110110111101101001… |
… | …010100111001010100111 |
3 | 120022000202120112211110122 |
4 | 332313231022213022213 |
5 | 1031241210301131120 |
6 | 13104435110312155 |
7 | 624066030354521 |
oct | 76675512471247 |
9 | 16260676484418 |
10 | 4320421114535 |
11 | 141630a0a4529 |
12 | 5993b035865b |
13 | 25454c627066 |
14 | 10d176666a11 |
15 | 775b6369a25 |
hex | 3eded2a72a7 |
4320421114535 has 8 divisors (see below), whose sum is σ = 5185450930320. Its totient is φ = 3455706496384.
The previous prime is 4320421114447. The next prime is 4320421114657. The reversal of 4320421114535 is 5354111240234.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4320421114535 - 222 = 4320416920231 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4320421114495 and 4320421114504.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 78769250 + ... + 78824079.
It is an arithmetic number, because the mean of its divisors is an integer number (648181366290).
Almost surely, 24320421114535 is an apocalyptic number.
4320421114535 is a deficient number, since it is larger than the sum of its proper divisors (865029815785).
4320421114535 is a wasteful number, since it uses less digits than its factorization.
4320421114535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 157598817.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 4320421114535 its reverse (5354111240234), we get a palindrome (9674532354769).
The spelling of 4320421114535 in words is "four trillion, three hundred twenty billion, four hundred twenty-one million, one hundred fourteen thousand, five hundred thirty-five".
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