Base | Representation |
---|---|
bin | 111110111001001101101… |
… | …111001010101110101001 |
3 | 120022011221111020021222120 |
4 | 332321031233022232221 |
5 | 1031303020033410441 |
6 | 13105303544541453 |
7 | 624154132660023 |
oct | 76711557125651 |
9 | 16264844207876 |
10 | 4322041310121 |
11 | 1416a7070a447 |
12 | 599782a81889 |
13 | 25474a1b1282 |
14 | 10d28b8d7013 |
15 | 7765d707966 |
hex | 3ee4dbcaba9 |
4322041310121 has 4 divisors (see below), whose sum is σ = 5762721746832. Its totient is φ = 2881360873412.
The previous prime is 4322041310117. The next prime is 4322041310141. The reversal of 4322041310121 is 1210131402234.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4322041310121 - 22 = 4322041310117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4322041310091 and 4322041310100.
It is not an unprimeable number, because it can be changed into a prime (4322041310141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 720340218351 + ... + 720340218356.
It is an arithmetic number, because the mean of its divisors is an integer number (1440680436708).
Almost surely, 24322041310121 is an apocalyptic number.
It is an amenable number.
4322041310121 is a deficient number, since it is larger than the sum of its proper divisors (1440680436711).
4322041310121 is a wasteful number, since it uses less digits than its factorization.
4322041310121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1440680436710.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 4322041310121 its reverse (1210131402234), we get a palindrome (5532172712355).
The spelling of 4322041310121 in words is "four trillion, three hundred twenty-two billion, forty-one million, three hundred ten thousand, one hundred twenty-one".
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