Base | Representation |
---|---|
bin | 110001001010011010110001… |
… | …0110101001101100100000010 |
3 | 2002201010220100210221220111110 |
4 | 1202110311202311031210002 |
5 | 423140101010210022424 |
6 | 4131420221251424150 |
7 | 160041535145620221 |
oct | 14224654265154402 |
9 | 2081126323856443 |
10 | 432440440314114 |
11 | 115874a62949431 |
12 | 40601a305b5056 |
13 | 1573ac5cbca03b |
14 | 78b032c4b0cb8 |
15 | 34edb7cc8dc29 |
hex | 1894d62d4d902 |
432440440314114 has 16 divisors (see below), whose sum is σ = 865084813921440. Its totient is φ = 144112824555840.
The previous prime is 432440440314083. The next prime is 432440440314137. The reversal of 432440440314114 is 411413044044234.
It is a super-3 number, since 3×4324404403141143 (a number of 45 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8497192984 + ... + 8497243875.
It is an arithmetic number, because the mean of its divisors is an integer number (54067800870090).
Almost surely, 2432440440314114 is an apocalyptic number.
432440440314114 is an abundant number, since it is smaller than the sum of its proper divisors (432644373607326).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
432440440314114 is a wasteful number, since it uses less digits than its factorization.
432440440314114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16994441105.
The product of its (nonzero) digits is 294912, while the sum is 39.
Adding to 432440440314114 its reverse (411413044044234), we get a palindrome (843853484358348).
The spelling of 432440440314114 in words is "four hundred thirty-two trillion, four hundred forty billion, four hundred forty million, three hundred fourteen thousand, one hundred fourteen".
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