Base | Representation |
---|---|
bin | 1100100101100110011… |
… | …11111011010000010011 |
3 | 1112100100221121222110111 |
4 | 12102303033323100103 |
5 | 24041232012314011 |
6 | 530404542142151 |
7 | 43150565364412 |
oct | 6226317732023 |
9 | 1470327558414 |
10 | 432504026131 |
11 | 15747327a311 |
12 | 6b9a4881957 |
13 | 31a287122b8 |
14 | 16d0cdc9479 |
15 | b3b5296121 |
hex | 64b33fb413 |
432504026131 has 4 divisors (see below), whose sum is σ = 432708715432. Its totient is φ = 432299336832.
The previous prime is 432504026113. The next prime is 432504026159. The reversal of 432504026131 is 131620405234.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 432504026131 - 217 = 432503895059 is a prime.
It is a super-2 number, since 2×4325040261312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 432504026093 and 432504026102.
It is not an unprimeable number, because it can be changed into a prime (432504026431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102341481 + ... + 102345706.
It is an arithmetic number, because the mean of its divisors is an integer number (108177178858).
Almost surely, 2432504026131 is an apocalyptic number.
432504026131 is a deficient number, since it is larger than the sum of its proper divisors (204689301).
432504026131 is a wasteful number, since it uses less digits than its factorization.
432504026131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 204689300.
The product of its (nonzero) digits is 17280, while the sum is 31.
The spelling of 432504026131 in words is "four hundred thirty-two billion, five hundred four million, twenty-six thousand, one hundred thirty-one".
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