Base | Representation |
---|---|
bin | 101000010010000110… |
… | …011100001010001011 |
3 | 11010122101210220010212 |
4 | 220102012130022023 |
5 | 1202040324213201 |
6 | 31511553231335 |
7 | 3060600263201 |
oct | 502206341213 |
9 | 133571726125 |
10 | 43253351051 |
11 | 17386430919 |
12 | 847156254b |
13 | 41040b0861 |
14 | 21446c3071 |
15 | 11d2422abb |
hex | a1219c28b |
43253351051 has 4 divisors (see below), whose sum is σ = 43256275272. Its totient is φ = 43250426832.
The previous prime is 43253351047. The next prime is 43253351081. The reversal of 43253351051 is 15015335234.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 43253351051 - 22 = 43253351047 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 43253350999 and 43253351017.
It is not an unprimeable number, because it can be changed into a prime (43253351081) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1439810 + ... + 1469543.
It is an arithmetic number, because the mean of its divisors is an integer number (10814068818).
Almost surely, 243253351051 is an apocalyptic number.
43253351051 is a deficient number, since it is larger than the sum of its proper divisors (2924221).
43253351051 is a wasteful number, since it uses less digits than its factorization.
43253351051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2924220.
The product of its (nonzero) digits is 27000, while the sum is 32.
Adding to 43253351051 its reverse (15015335234), we get a palindrome (58268686285).
The spelling of 43253351051 in words is "forty-three billion, two hundred fifty-three million, three hundred fifty-one thousand, fifty-one".
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