Base | Representation |
---|---|
bin | 111111000000101110110… |
… | …110011011101011001001 |
3 | 120022221210000122102221122 |
4 | 333000232312123223021 |
5 | 1031421032420233213 |
6 | 13113120530245025 |
7 | 624561144453134 |
oct | 77005666335311 |
9 | 16287700572848 |
10 | 4330113055433 |
11 | 141a432a30140 |
12 | 59b256126775 |
13 | 255435554429 |
14 | 10d81591921b |
15 | 77982175d08 |
hex | 3f02ed9bac9 |
4330113055433 has 16 divisors (see below), whose sum is σ = 4810334791680. Its totient is φ = 3864784467600.
The previous prime is 4330113055417. The next prime is 4330113055469. The reversal of 4330113055433 is 3345503110334.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 4330113055433 - 24 = 4330113055417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4330113055393 and 4330113055402.
It is not an unprimeable number, because it can be changed into a prime (4330113055493) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11412335 + ... + 11785652.
It is an arithmetic number, because the mean of its divisors is an integer number (300645924480).
Almost surely, 24330113055433 is an apocalyptic number.
It is an amenable number.
4330113055433 is a deficient number, since it is larger than the sum of its proper divisors (480221736247).
4330113055433 is a wasteful number, since it uses less digits than its factorization.
4330113055433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23198308.
The product of its (nonzero) digits is 97200, while the sum is 35.
Adding to 4330113055433 its reverse (3345503110334), we get a palindrome (7675616165767).
The spelling of 4330113055433 in words is "four trillion, three hundred thirty billion, one hundred thirteen million, fifty-five thousand, four hundred thirty-three".
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