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43303201120034 = 2414312281112059
BaseRepresentation
bin10011101100010010011111…
…11010111001111100100010
312200022202010112121001122222
421312021033322321330202
521133434423441320114
6232033114352031042
712056360456226602
oct1166111772717442
9180282115531588
1043303201120034
111288586a135999
124a3454a532482
131b2162219781b
14a99c59710c02
15501637b8e98e
hex27624feb9f22

43303201120034 has 16 divisors (see below), whose sum is σ = 68086485260640. Its totient is φ = 20632268257440.

The previous prime is 43303201120033. The next prime is 43303201120177. The reversal of 43303201120034 is 43002110230334.

It is a super-2 number, since 2×433032011200342 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43303201119985 and 43303201120012.

It is not an unprimeable number, because it can be changed into a prime (43303201120033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6140552504 + ... + 6140559555.

It is an arithmetic number, because the mean of its divisors is an integer number (4255405328790).

Almost surely, 243303201120034 is an apocalyptic number.

43303201120034 is a deficient number, since it is larger than the sum of its proper divisors (24783284140606).

43303201120034 is a wasteful number, since it uses less digits than its factorization.

43303201120034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12281112145.

The product of its (nonzero) digits is 5184, while the sum is 26.

Adding to 43303201120034 its reverse (43002110230334), we get a palindrome (86305311350368).

The spelling of 43303201120034 in words is "forty-three trillion, three hundred three billion, two hundred one million, one hundred twenty thousand, thirty-four".

Divisors: 1 2 41 43 82 86 1763 3526 12281112059 24562224118 503525594419 528087818537 1007051188838 1056175637074 21651600560017 43303201120034