Base | Representation |
---|---|
bin | 10011101100010010011111… |
… | …11010111001111100100010 |
3 | 12200022202010112121001122222 |
4 | 21312021033322321330202 |
5 | 21133434423441320114 |
6 | 232033114352031042 |
7 | 12056360456226602 |
oct | 1166111772717442 |
9 | 180282115531588 |
10 | 43303201120034 |
11 | 1288586a135999 |
12 | 4a3454a532482 |
13 | 1b2162219781b |
14 | a99c59710c02 |
15 | 501637b8e98e |
hex | 27624feb9f22 |
43303201120034 has 16 divisors (see below), whose sum is σ = 68086485260640. Its totient is φ = 20632268257440.
The previous prime is 43303201120033. The next prime is 43303201120177. The reversal of 43303201120034 is 43002110230334.
It is a super-2 number, since 2×433032011200342 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 43303201119985 and 43303201120012.
It is not an unprimeable number, because it can be changed into a prime (43303201120033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6140552504 + ... + 6140559555.
It is an arithmetic number, because the mean of its divisors is an integer number (4255405328790).
Almost surely, 243303201120034 is an apocalyptic number.
43303201120034 is a deficient number, since it is larger than the sum of its proper divisors (24783284140606).
43303201120034 is a wasteful number, since it uses less digits than its factorization.
43303201120034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12281112145.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 43303201120034 its reverse (43002110230334), we get a palindrome (86305311350368).
The spelling of 43303201120034 in words is "forty-three trillion, three hundred three billion, two hundred one million, one hundred twenty thousand, thirty-four".
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