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4331002133021 = 40910589247269
BaseRepresentation
bin111111000001100011110…
…101111111101000011101
3120100001001222121021010012
4333001203311333220131
51031424343021224041
613113345050253005
7624622161501104
oct77014365775035
916301058537105
104331002133021
11141a849882303
1259b463a27165
132555477c5445
1410d89ba3103b
15779d52463eb
hex3f063d7fa1d

4331002133021 has 4 divisors (see below), whose sum is σ = 4341591380700. Its totient is φ = 4320412885344.

The previous prime is 4331002133009. The next prime is 4331002133071. The reversal of 4331002133021 is 1203312001334.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3241389748996 + 1089612384025 = 1800386^2 + 1043845^2 .

It is a cyclic number.

It is not a de Polignac number, because 4331002133021 - 222 = 4330997938717 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4331002133071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5294623226 + ... + 5294624043.

It is an arithmetic number, because the mean of its divisors is an integer number (1085397845175).

Almost surely, 24331002133021 is an apocalyptic number.

It is an amenable number.

4331002133021 is a deficient number, since it is larger than the sum of its proper divisors (10589247679).

4331002133021 is a wasteful number, since it uses less digits than its factorization.

4331002133021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10589247678.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 4331002133021 its reverse (1203312001334), we get a palindrome (5534314134355).

The spelling of 4331002133021 in words is "four trillion, three hundred thirty-one billion, two million, one hundred thirty-three thousand, twenty-one".

Divisors: 1 409 10589247269 4331002133021