43311432041 has 4 divisors (see below), whose sum is σ = 43577146512. Its totient is φ = 43045717572.

The previous prime is 43311432023. The next prime is 43311432067. The reversal of 43311432041 is 14023411334.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 43311432041 - 2¹⁴ = 43311415657 is a prime.

It is a super-2 number, since 2×43311432041² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 43311432041.

It is not an unprimeable number, because it can be changed into a prime (43311432011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132856991 + ... + 132857316.

It is an arithmetic number, because the mean of its divisors is an integer number (10894286628).

Almost surely, 2^43311432041 is an apocalyptic number.

It is an amenable number.

43311432041 is a deficient number, since it is larger than the sum of its proper divisors (265714471).

43311432041 is a wasteful number, since it uses less digits than its factorization.

43311432041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 265714470.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 43311432041 its reverse (14023411334), we get a palindrome (57334843375).

The spelling of 43311432041 in words is "forty-three billion, three hundred eleven million, four hundred thirty-two thousand, forty-one".