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433121420401 = 914574735793
BaseRepresentation
bin1100100110110000000…
…11000110010001110001
31112101221222100212011221
412103120003012101301
524044013040423101
6530550115105041
743202103220615
oct6233003062161
91471858325157
10433121420401
1115775a82880a
126bb375a2181
1331ac65bb257
1416d6adbd345
15b3ee59caa1
hex64d80c6471

433121420401 has 4 divisors (see below), whose sum is σ = 433126247652. Its totient is φ = 433116593152.

The previous prime is 433121420399. The next prime is 433121420411. The reversal of 433121420401 is 104024121334.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 90661210000 + 342460210401 = 301100^2 + 585201^2 .

It is a cyclic number.

It is not a de Polignac number, because 433121420401 - 21 = 433121420399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (433121420411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2276440 + ... + 2459353.

It is an arithmetic number, because the mean of its divisors is an integer number (108281561913).

Almost surely, 2433121420401 is an apocalyptic number.

It is an amenable number.

433121420401 is a deficient number, since it is larger than the sum of its proper divisors (4827251).

433121420401 is an equidigital number, since it uses as much as digits as its factorization.

433121420401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4827250.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 433121420401 its reverse (104024121334), we get a palindrome (537145541735).

The spelling of 433121420401 in words is "four hundred thirty-three billion, one hundred twenty-one million, four hundred twenty thousand, four hundred one".

Divisors: 1 91457 4735793 433121420401