4331221112131 has 6 divisors (see below), whose sum is σ = 4527722637620. Its totient is φ = 4142907150228.

The previous prime is 4331221112117. The next prime is 4331221112137. The reversal of 4331221112131 is 1312111221334.

4331221112131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 4331221112131 - 2⁹ = 4331221111619 is a prime.

It is a super-2 number, since 2×4331221112131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4331221112096 and 4331221112105.

It is not an unprimeable number, because it can be changed into a prime (4331221112137) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 4093781241 + ... + 4093782298.

Almost surely, 2^{4331221112131} is an apocalyptic number.

4331221112131 is a deficient number, since it is larger than the sum of its proper divisors (196501525489).

4331221112131 is an equidigital number, since it uses as much as digits as its factorization.

4331221112131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8187563585 (or 8187563562 counting only the distinct ones).

The product of its digits is 864, while the sum is 25.

Adding to 4331221112131 its reverse (1312111221334), we get a palindrome (5643332333465).

The spelling of 4331221112131 in words is "four trillion, three hundred thirty-one billion, two hundred twenty-one million, one hundred twelve thousand, one hundred thirty-one".