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4331272420721 = 32531331470157
BaseRepresentation
bin111111000001110011111…
…101000011110101110001
3120100001202211012022010202
4333001303331003311301
51031430421214430341
613113431543404545
7624631653060641
oct77016375036561
916301684168122
104331272420721
11141a978402474
1259b51a453755
1325558b7bc1ac
1410d8c58ac521
15779edd3679b
hex3f073f43d71

4331272420721 has 4 divisors (see below), whose sum is σ = 4332603894132. Its totient is φ = 4329940947312.

The previous prime is 4331272420711. The next prime is 4331272420723. The reversal of 4331272420721 is 1270242721334.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3136866054400 + 1194406366321 = 1771120^2 + 1092889^2 .

It is a cyclic number.

It is not a de Polignac number, because 4331272420721 - 210 = 4331272419697 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (4331272420723) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 665731826 + ... + 665738331.

It is an arithmetic number, because the mean of its divisors is an integer number (1083150973533).

Almost surely, 24331272420721 is an apocalyptic number.

It is an amenable number.

4331272420721 is a deficient number, since it is larger than the sum of its proper divisors (1331473411).

4331272420721 is a wasteful number, since it uses less digits than its factorization.

4331272420721 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1331473410.

The product of its (nonzero) digits is 112896, while the sum is 38.

The spelling of 4331272420721 in words is "four trillion, three hundred thirty-one billion, two hundred seventy-two million, four hundred twenty thousand, seven hundred twenty-one".

Divisors: 1 3253 1331470157 4331272420721