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433130240113 = 19194911696423
BaseRepresentation
bin1100100110110001001…
…00101111100001110001
31112101222120221221112221
412103120210233201301
524044022320140423
6530551032121041
743202241203224
oct6233044574161
91471876857487
10433130240113
1115776480212a
126bb3a536181
1331ac838880c
1416d6c2375bb
15b400240e5d
hex64d892f871

433130240113 has 8 divisors (see below), whose sum is σ = 456160536000. Its totient is φ = 410123341008.

The previous prime is 433130240111. The next prime is 433130240117. The reversal of 433130240113 is 311042031334.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 433130240113 - 21 = 433130240111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (433130240111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5811181 + ... + 5885242.

It is an arithmetic number, because the mean of its divisors is an integer number (57020067000).

Almost surely, 2433130240113 is an apocalyptic number.

It is an amenable number.

433130240113 is a deficient number, since it is larger than the sum of its proper divisors (23030295887).

433130240113 is a wasteful number, since it uses less digits than its factorization.

433130240113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11698391.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 433130240113 its reverse (311042031334), we get a palindrome (744172271447).

The spelling of 433130240113 in words is "four hundred thirty-three billion, one hundred thirty million, two hundred forty thousand, one hundred thirteen".

Divisors: 1 19 1949 37031 11696423 222232037 22796328427 433130240113