Base | Representation |
---|---|
bin | 111111000001110110010… |
… | …000010001110011101101 |
3 | 120100001212111210222221011 |
4 | 333001312100101303231 |
5 | 1031431011104404401 |
6 | 13113435442505221 |
7 | 624632632104112 |
oct | 77016620216355 |
9 | 16301774728834 |
10 | 4331311013101 |
11 | 141a9981714a6 |
12 | 59b52b365211 |
13 | 2555967b2117 |
14 | 10d8caa76909 |
15 | 77a0240b451 |
hex | 3f076411ced |
4331311013101 has 4 divisors (see below), whose sum is σ = 4353988034304. Its totient is φ = 4308633991900.
The previous prime is 4331311013063. The next prime is 4331311013123. The reversal of 4331311013101 is 1013101131334.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4331311013101 - 217 = 4331310882029 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4331311013201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11338510315 + ... + 11338510696.
It is an arithmetic number, because the mean of its divisors is an integer number (1088497008576).
Almost surely, 24331311013101 is an apocalyptic number.
It is an amenable number.
4331311013101 is a deficient number, since it is larger than the sum of its proper divisors (22677021203).
4331311013101 is a wasteful number, since it uses less digits than its factorization.
4331311013101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22677021202.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 4331311013101 its reverse (1013101131334), we get a palindrome (5344412144435).
The spelling of 4331311013101 in words is "four trillion, three hundred thirty-one billion, three hundred eleven million, thirteen thousand, one hundred one".
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