433131341141 has 4 divisors (see below), whose sum is σ = 443204163072. Its totient is φ = 423058519212.

The previous prime is 433131341101. The next prime is 433131341171. The reversal of 433131341141 is 141143131334.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 433131341141 - 2¹⁸ = 433131078997 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (433131341101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5036410901 + ... + 5036410986.

It is an arithmetic number, because the mean of its divisors is an integer number (110801040768).

Almost surely, 2^433131341141 is an apocalyptic number.

It is an amenable number.

433131341141 is a deficient number, since it is larger than the sum of its proper divisors (10072821931).

433131341141 is a wasteful number, since it uses less digits than its factorization.

433131341141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10072821930.

The product of its digits is 5184, while the sum is 29.

Adding to 433131341141 its reverse (141143131334), we get a palindrome (574274472475).

The spelling of 433131341141 in words is "four hundred thirty-three billion, one hundred thirty-one million, three hundred forty-one thousand, one hundred forty-one".