Base | Representation |
---|---|
bin | 111111000001110111000… |
… | …010101000101011111101 |
3 | 120100001220102122200011211 |
4 | 333001313002220223331 |
5 | 1031431022444322023 |
6 | 13113441033444421 |
7 | 624633152234536 |
oct | 77016702505375 |
9 | 16301812580154 |
10 | 4331324214013 |
11 | 141a9a4668545 |
12 | 59b533870711 |
13 | 255599454904 |
14 | 10d8cc71168d |
15 | 77a03667a0d |
hex | 3f0770a8afd |
4331324214013 has 4 divisors (see below), whose sum is σ = 4331365581088. Its totient is φ = 4331282846940.
The previous prime is 4331324213987. The next prime is 4331324214043. The reversal of 4331324214013 is 3104124231334.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4331324214013 - 29 = 4331324213501 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4331324214043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20526081 + ... + 20736022.
It is an arithmetic number, because the mean of its divisors is an integer number (1082841395272).
Almost surely, 24331324214013 is an apocalyptic number.
It is an amenable number.
4331324214013 is a deficient number, since it is larger than the sum of its proper divisors (41367075).
4331324214013 is a wasteful number, since it uses less digits than its factorization.
4331324214013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41367074.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 4331324214013 its reverse (3104124231334), we get a palindrome (7435448445347).
The spelling of 4331324214013 in words is "four trillion, three hundred thirty-one billion, three hundred twenty-four million, two hundred fourteen thousand, thirteen".
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