Base | Representation |
---|---|
bin | 111111000001111101011… |
… | …010000111010100110000 |
3 | 120100002011212122121001201 |
4 | 333001331122013110300 |
5 | 1031431232321011422 |
6 | 13113455411140544 |
7 | 624635620204552 |
oct | 77017532072460 |
9 | 16302155577051 |
10 | 4331431032112 |
11 | 141aa49996568 |
12 | 59b5635a4754 |
13 | 2555b56148a2 |
14 | 10d8dc9994d2 |
15 | 77a0cc17727 |
hex | 3f07d687530 |
4331431032112 has 20 divisors (see below), whose sum is σ = 8392322194056. Its totient is φ = 2165670465920.
The previous prime is 4331431032109. The next prime is 4331431032179. The reversal of 4331431032112 is 2112301341334.
It is a super-2 number, since 2×43314310321122 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2015533 + ... + 3567244.
Almost surely, 24331431032112 is an apocalyptic number.
It is an amenable number.
4331431032112 is a deficient number, since it is larger than the sum of its proper divisors (4060891161944).
4331431032112 is a wasteful number, since it uses less digits than its factorization.
4331431032112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5631276 (or 5631270 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 4331431032112 its reverse (2112301341334), we get a palindrome (6443732373446).
The spelling of 4331431032112 in words is "four trillion, three hundred thirty-one billion, four hundred thirty-one million, thirty-two thousand, one hundred twelve".
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