Base | Representation |
---|---|
bin | 1100100110110010101… |
… | …10111100011100001001 |
3 | 1112102000111201112210121 |
4 | 12103121112330130021 |
5 | 24044034202301301 |
6 | 530552222143241 |
7 | 43202461103641 |
oct | 6233126743411 |
9 | 1472014645717 |
10 | 433143400201 |
11 | 157771180536 |
12 | 6bb42a21b21 |
13 | 31acb015855 |
14 | 16d6dca1521 |
15 | b4014903a1 |
hex | 64d95bc709 |
433143400201 has 8 divisors (see below), whose sum is σ = 434227345344. Its totient is φ = 432059717040.
The previous prime is 433143400169. The next prime is 433143400213. The reversal of 433143400201 is 102004341334.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 433143400201 - 25 = 433143400169 is a prime.
It is a super-2 number, since 2×4331434002012 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (433143400601) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3485010 + ... + 3607156.
It is an arithmetic number, because the mean of its divisors is an integer number (54278418168).
Almost surely, 2433143400201 is an apocalyptic number.
It is an amenable number.
433143400201 is a deficient number, since it is larger than the sum of its proper divisors (1083945143).
433143400201 is a wasteful number, since it uses less digits than its factorization.
433143400201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 130991.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 433143400201 its reverse (102004341334), we get a palindrome (535147741535).
The spelling of 433143400201 in words is "four hundred thirty-three billion, one hundred forty-three million, four hundred thousand, two hundred one".
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