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4331523052001 = 20149921496499
BaseRepresentation
bin111111000010000010111…
…001001001000111100001
3120100002102021210200121202
4333002002321021013201
51031431424400131001
613113512455330545
7624641115312245
oct77020271110741
916302367720552
104331523052001
11141aa96927462
1259b58a380a55
132555cb6c3022
1410d90acb0425
1577a15d4296b
hex3f082e491e1

4331523052001 has 4 divisors (see below), whose sum is σ = 4331544750000. Its totient is φ = 4331501354004.

The previous prime is 4331523051943. The next prime is 4331523052007. The reversal of 4331523052001 is 1002503251334.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4331523052001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4331523052007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10546751 + ... + 10949748.

It is an arithmetic number, because the mean of its divisors is an integer number (1082886187500).

Almost surely, 24331523052001 is an apocalyptic number.

It is an amenable number.

4331523052001 is a deficient number, since it is larger than the sum of its proper divisors (21697999).

4331523052001 is a wasteful number, since it uses less digits than its factorization.

4331523052001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21697998.

The product of its (nonzero) digits is 10800, while the sum is 29.

The spelling of 4331523052001 in words is "four trillion, three hundred thirty-one billion, five hundred twenty-three million, fifty-two thousand, one".

Divisors: 1 201499 21496499 4331523052001