Base | Representation |
---|---|
bin | 111111000010100000010… |
… | …101110101011111010001 |
3 | 120100010200201110120221210 |
4 | 333002200111311133101 |
5 | 1031433432340104131 |
6 | 13114033505010333 |
7 | 624656264622402 |
oct | 77024025653721 |
9 | 16303621416853 |
10 | 4332017113041 |
11 | 142021a7a7872 |
12 | 59b6a79239a9 |
13 | 255679b78b37 |
14 | 10d95675b9a9 |
15 | 77a443d6146 |
hex | 3f0a05757d1 |
4332017113041 has 8 divisors (see below), whose sum is σ = 5776048559584. Its totient is φ = 2887998537600.
The previous prime is 4332017113033. The next prime is 4332017113049. The reversal of 4332017113041 is 1403117102334.
It is an interprime number because it is at equal distance from previous prime (4332017113033) and next prime (4332017113049).
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 4332017113041 - 23 = 4332017113033 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (4332017113049) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2402971 + ... + 3799776.
It is an arithmetic number, because the mean of its divisors is an integer number (722006069948).
Almost surely, 24332017113041 is an apocalyptic number.
It is an amenable number.
4332017113041 is a deficient number, since it is larger than the sum of its proper divisors (1444031446543).
4332017113041 is a wasteful number, since it uses less digits than its factorization.
4332017113041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6435551.
The product of its (nonzero) digits is 6048, while the sum is 30.
The spelling of 4332017113041 in words is "four trillion, three hundred thirty-two billion, seventeen million, one hundred thirteen thousand, forty-one".
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