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4332020114101 = 132715232143481
BaseRepresentation
bin111111000010100000100…
…001010010001010110101
3120100010200221010001122011
4333002200201102022311
51031433434122122401
613114034053204221
7624656332262011
oct77024041221265
916303627101564
104332020114101
111420221467589
1259b6a8930671
1325567a689b04
1410d956cdd541
1577a447ca451
hex3f0a08522b5

4332020114101 has 8 divisors (see below), whose sum is σ = 4338133202304. Its totient is φ = 4325911318560.

The previous prime is 4332020114083. The next prime is 4332020114111. The reversal of 4332020114101 is 1014110202334.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4332020114101 - 213 = 4332020105909 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4332020114111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 949281 + ... + 3092761.

It is an arithmetic number, because the mean of its divisors is an integer number (542266650288).

Almost surely, 24332020114101 is an apocalyptic number.

It is an amenable number.

4332020114101 is a deficient number, since it is larger than the sum of its proper divisors (6113088203).

4332020114101 is a wasteful number, since it uses less digits than its factorization.

4332020114101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2146331.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 4332020114101 its reverse (1014110202334), we get a palindrome (5346130316435).

The spelling of 4332020114101 in words is "four trillion, three hundred thirty-two billion, twenty million, one hundred fourteen thousand, one hundred one".

Divisors: 1 1327 1523 2021021 2143481 2844399287 3264521563 4332020114101