Base | Representation |
---|---|
bin | 111111000010101110011… |
… | …010111010001100010111 |
3 | 120100011022011221100112212 |
4 | 333002232122322030113 |
5 | 1031434423322332210 |
6 | 13114113143504035 |
7 | 624665163444266 |
oct | 77025632721427 |
9 | 16304264840485 |
10 | 4332253324055 |
11 | 1420331072688 |
12 | 59b752a5801b |
13 | 2556b6aa1177 |
14 | 10d979c885dd |
15 | 77a59ee4805 |
hex | 3f0ae6ba317 |
4332253324055 has 16 divisors (see below), whose sum is σ = 5472371543520. Its totient is φ = 3283361059968.
The previous prime is 4332253323989. The next prime is 4332253324129. The reversal of 4332253324055 is 5504233522334.
It is a cyclic number.
It is not a de Polignac number, because 4332253324055 - 28 = 4332253323799 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18076589 + ... + 18314681.
It is an arithmetic number, because the mean of its divisors is an integer number (342023221470).
Almost surely, 24332253324055 is an apocalyptic number.
4332253324055 is a deficient number, since it is larger than the sum of its proper divisors (1140118219465).
4332253324055 is a wasteful number, since it uses less digits than its factorization.
4332253324055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 429650.
The product of its (nonzero) digits is 1296000, while the sum is 41.
Adding to 4332253324055 its reverse (5504233522334), we get a palindrome (9836486846389).
The spelling of 4332253324055 in words is "four trillion, three hundred thirty-two billion, two hundred fifty-three million, three hundred twenty-four thousand, fifty-five".
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