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4332300000034 = 22166150000017
BaseRepresentation
bin111111000010110001001…
…100111101101100100010
3120100011102102202201221211
4333002301030331230202
51031440022300000114
613114121532140334
7624666301255666
oct77026114755442
916304372681854
104332300000034
111420355452a76
1259b7666076aa
132556c36645a6
1410d9821588a6
1577a5e1646c4
hex3f0b133db22

4332300000034 has 4 divisors (see below), whose sum is σ = 6498450000054. Its totient is φ = 2166150000016.

The previous prime is 4332299999999. The next prime is 4332300000037. The reversal of 4332300000034 is 4300000032334.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 4071327169009 + 260972831025 = 2017753^2 + 510855^2 .

It is a junction number, because it is equal to n+sod(n) for n = 4332299999960 and 4332300000014.

It is not an unprimeable number, because it can be changed into a prime (4332300000037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1083075000007 + ... + 1083075000010.

Almost surely, 24332300000034 is an apocalyptic number.

4332300000034 is a deficient number, since it is larger than the sum of its proper divisors (2166150000020).

4332300000034 is a wasteful number, since it uses less digits than its factorization.

4332300000034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2166150000019.

The product of its (nonzero) digits is 2592, while the sum is 22.

Adding to 4332300000034 its reverse (4300000032334), we get a palindrome (8632300032368).

The spelling of 4332300000034 in words is "four trillion, three hundred thirty-two billion, three hundred million, thirty-four", and thus it is an aban number.

Divisors: 1 2 2166150000017 4332300000034