Base | Representation |
---|---|
bin | 1100100110111101001… |
… | …01100111110101010010 |
3 | 1112102020121210212222211 |
4 | 12103132211213311102 |
5 | 24044224132242114 |
6 | 531005034422334 |
7 | 43204604610466 |
oct | 6233645476522 |
9 | 1472217725884 |
10 | 433231134034 |
11 | 157806754236 |
12 | 6bb682919aa |
13 | 31b1325316a |
14 | 16d7b7bc4a6 |
15 | b4090206c4 |
hex | 64de967d52 |
433231134034 has 8 divisors (see below), whose sum is σ = 653833491120. Its totient is φ = 215286636996.
The previous prime is 433231134031. The next prime is 433231134059. The reversal of 433231134034 is 430431132334.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×4332311340342 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 433231133987 and 433231134005.
It is not an unprimeable number, because it can be changed into a prime (433231134031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 664464604 + ... + 664465255.
It is an arithmetic number, because the mean of its divisors is an integer number (81729186390).
Almost surely, 2433231134034 is an apocalyptic number.
433231134034 is a deficient number, since it is larger than the sum of its proper divisors (220602357086).
433231134034 is a wasteful number, since it uses less digits than its factorization.
433231134034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1328930024.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 433231134034 its reverse (430431132334), we get a palindrome (863662266368).
The spelling of 433231134034 in words is "four hundred thirty-three billion, two hundred thirty-one million, one hundred thirty-four thousand, thirty-four".
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