Base | Representation |
---|---|
bin | 111111000011100011010… |
… | …101001101010101100111 |
3 | 120100020121001022002021120 |
4 | 333003203111031111213 |
5 | 1031443233100201210 |
6 | 13114341214145023 |
7 | 625026162655146 |
oct | 77034325152547 |
9 | 16306531262246 |
10 | 4333141022055 |
11 | 142074716229a |
12 | 59b9601b2173 |
13 | 2557c897b261 |
14 | 10da21b2175d |
15 | 77aacde1270 |
hex | 3f0e354d567 |
4333141022055 has 16 divisors (see below), whose sum is σ = 7120404707424. Its totient is φ = 2248548854400.
The previous prime is 4333141022047. The next prime is 4333141022059. The reversal of 4333141022055 is 5502201413334.
It is not a de Polignac number, because 4333141022055 - 23 = 4333141022047 is a prime.
It is a super-2 number, since 2×43331410220552 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4333141022059) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3903730096 + ... + 3903731205.
It is an arithmetic number, because the mean of its divisors is an integer number (445025294214).
Almost surely, 24333141022055 is an apocalyptic number.
4333141022055 is a deficient number, since it is larger than the sum of its proper divisors (2787263685369).
4333141022055 is a wasteful number, since it uses less digits than its factorization.
4333141022055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7807461346.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 4333141022055 its reverse (5502201413334), we get a palindrome (9835342435389).
The spelling of 4333141022055 in words is "four trillion, three hundred thirty-three billion, one hundred forty-one million, twenty-two thousand, fifty-five".
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