Base | Representation |
---|---|
bin | 111111000100010111101… |
… | …110001111100111001011 |
3 | 120100022212022020210121210 |
4 | 333010113232033213023 |
5 | 1032002033110001303 |
6 | 13115004333504203 |
7 | 625060025110515 |
oct | 77042756174713 |
9 | 16308768223553 |
10 | 4334020000203 |
11 | 1421058336613 |
12 | 59bb66642063 |
13 | 255908ac437a |
14 | 10daa6768bb5 |
15 | 77b10169203 |
hex | 3f117b8f9cb |
4334020000203 has 32 divisors (see below), whose sum is σ = 5950942566912. Its totient is φ = 2803996640000.
The previous prime is 4334020000199. The next prime is 4334020000217. The reversal of 4334020000203 is 3020000204334.
It is a cyclic number.
It is not a de Polignac number, because 4334020000203 - 22 = 4334020000199 is a prime.
It is a super-2 number, since 2×43340200002032 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 4334020000203.
It is not an unprimeable number, because it can be changed into a prime (4334020000403) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 23774026 + ... + 23955632.
It is an arithmetic number, because the mean of its divisors is an integer number (185966955216).
Almost surely, 24334020000203 is an apocalyptic number.
4334020000203 is a deficient number, since it is larger than the sum of its proper divisors (1616922566709).
4334020000203 is a wasteful number, since it uses less digits than its factorization.
4334020000203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 182675.
The product of its (nonzero) digits is 1728, while the sum is 21.
Adding to 4334020000203 its reverse (3020000204334), we get a palindrome (7354020204537).
The spelling of 4334020000203 in words is "four trillion, three hundred thirty-four billion, twenty million, two hundred three", and thus it is an aban number.
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