43340403151 has 4 divisors (see below), whose sum is σ = 44738480704. Its totient is φ = 41942325600.

The previous prime is 43340403149. The next prime is 43340403167. The reversal of 43340403151 is 15130404334.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 43340403151 - 2¹ = 43340403149 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43340403101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 699038730 + ... + 699038791.

It is an arithmetic number, because the mean of its divisors is an integer number (11184620176).

Almost surely, 2^43340403151 is an apocalyptic number.

43340403151 is a deficient number, since it is larger than the sum of its proper divisors (1398077553).

43340403151 is a wasteful number, since it uses less digits than its factorization.

43340403151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1398077552.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 43340403151 its reverse (15130404334), we get a palindrome (58470807485).

The spelling of 43340403151 in words is "forty-three billion, three hundred forty million, four hundred three thousand, one hundred fifty-one".