Base | Representation |
---|---|
bin | 101000010111010101… |
… | …101011110000110001 |
3 | 11010212112011202210022 |
4 | 220113111223300301 |
5 | 1202230323430301 |
6 | 31524413013225 |
7 | 3063015255320 |
oct | 502725536061 |
9 | 133775152708 |
10 | 43341233201 |
11 | 17420aa5aa2 |
12 | 8496a84215 |
13 | 4119370826 |
14 | 215223c0b7 |
15 | 11d9ed1d1b |
hex | a1756bc31 |
43341233201 has 8 divisors (see below), whose sum is σ = 50467420224. Its totient is φ = 36448691760.
The previous prime is 43341233167. The next prime is 43341233213. The reversal of 43341233201 is 10233214334.
43341233201 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 43341233201 - 214 = 43341216817 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (43341233401) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 58410995 + ... + 58411736.
It is an arithmetic number, because the mean of its divisors is an integer number (6308427528).
Almost surely, 243341233201 is an apocalyptic number.
It is an amenable number.
43341233201 is a deficient number, since it is larger than the sum of its proper divisors (7126187023).
43341233201 is a wasteful number, since it uses less digits than its factorization.
43341233201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 116822791.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 43341233201 its reverse (10233214334), we get a palindrome (53574447535).
The spelling of 43341233201 in words is "forty-three billion, three hundred forty-one million, two hundred thirty-three thousand, two hundred one".
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