Base | Representation |
---|---|
bin | 1100100111010101010… |
… | …11111101111011100001 |
3 | 1112102202202202211212202 |
4 | 12103222223331323201 |
5 | 24100133113432001 |
6 | 531041125302545 |
7 | 43212621160124 |
oct | 6235253757341 |
9 | 1472682684782 |
10 | 433434124001 |
11 | 15790029963a |
12 | 70004264a55 |
13 | 31b46316378 |
14 | 16d9a73c3bb |
15 | b41bc6a96b |
hex | 64eaafdee1 |
433434124001 has 4 divisors (see below), whose sum is σ = 433550673600. Its totient is φ = 433317574404.
The previous prime is 433434123979. The next prime is 433434124027. The reversal of 433434124001 is 100421434334.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-433434124001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (433434127001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58269221 + ... + 58276658.
It is an arithmetic number, because the mean of its divisors is an integer number (108387668400).
Almost surely, 2433434124001 is an apocalyptic number.
It is an amenable number.
433434124001 is a deficient number, since it is larger than the sum of its proper divisors (116549599).
433434124001 is a wasteful number, since it uses less digits than its factorization.
433434124001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 116549598.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 433434124001 its reverse (100421434334), we get a palindrome (533855558335).
The spelling of 433434124001 in words is "four hundred thirty-three billion, four hundred thirty-four million, one hundred twenty-four thousand, one".
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