Base | Representation |
---|---|
bin | 111111000100101111001… |
… | …011000100000100000101 |
3 | 120100100212201120011021110 |
4 | 333010233023010010011 |
5 | 1032003334314243140 |
6 | 13115111350235233 |
7 | 625102543162305 |
oct | 77045713040405 |
9 | 16310781504243 |
10 | 4334413431045 |
11 | 142123a424a75 |
12 | 5a0056355b19 |
13 | 25596c475899 |
14 | 10db02add605 |
15 | 77b34981380 |
hex | 3f12f2c4105 |
4334413431045 has 16 divisors (see below), whose sum is σ = 7174201541760. Its totient is φ = 2231973812544.
The previous prime is 4334413431001. The next prime is 4334413431109. The reversal of 4334413431045 is 5401343144334.
It is not a de Polignac number, because 4334413431045 - 29 = 4334413430533 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4334413430994 and 4334413431012.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4982083969 + ... + 4982084838.
It is an arithmetic number, because the mean of its divisors is an integer number (448387596360).
Almost surely, 24334413431045 is an apocalyptic number.
It is an amenable number.
4334413431045 is a deficient number, since it is larger than the sum of its proper divisors (2839788110715).
4334413431045 is a wasteful number, since it uses less digits than its factorization.
4334413431045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9964168844.
The product of its (nonzero) digits is 414720, while the sum is 39.
Adding to 4334413431045 its reverse (5401343144334), we get a palindrome (9735756575379).
The spelling of 4334413431045 in words is "four trillion, three hundred thirty-four billion, four hundred thirteen million, four hundred thirty-one thousand, forty-five".
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