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434010014303 = 2272892166109
BaseRepresentation
bin1100101000011010000…
…00110100001001011111
31112111020220102002212012
412110031000310021133
524102323030424203
6531214220501435
743233113152445
oct6241500641137
91474226362765
10434010014303
1115807637a538
12701450aa87b
1331c08720068
141701300ab95
15b4525c4bd8
hex650d03425f

434010014303 has 8 divisors (see below), whose sum is σ = 435943619760. Its totient is φ = 432076599360.

The previous prime is 434010014299. The next prime is 434010014341. The reversal of 434010014303 is 303410010434.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 434010014303 - 22 = 434010014299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (434010014003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6532013 + ... + 6598121.

It is an arithmetic number, because the mean of its divisors is an integer number (54492952470).

Almost surely, 2434010014303 is an apocalyptic number.

434010014303 is a deficient number, since it is larger than the sum of its proper divisors (1933605457).

434010014303 is a wasteful number, since it uses less digits than its factorization.

434010014303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 95257.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 434010014303 its reverse (303410010434), we get a palindrome (737420024737).

The spelling of 434010014303 in words is "four hundred thirty-four billion, ten million, fourteen thousand, three hundred three".

Divisors: 1 227 28921 66109 6565067 15006743 1911938389 434010014303