Base | Representation |
---|---|
bin | 111111001010000100000… |
… | …001101011010100001001 |
3 | 120100220122021001121112220 |
4 | 333022010001223110021 |
5 | 1032102042243013113 |
6 | 13121455031124253 |
7 | 625364342213103 |
oct | 77120401532411 |
9 | 16326567047486 |
10 | 4340132001033 |
11 | 1423704405274 |
12 | 5a1191513689 |
13 | 2563711460ca |
14 | 1100c63b0573 |
15 | 77d6ba27523 |
hex | 3f28406b509 |
4340132001033 has 8 divisors (see below), whose sum is σ = 5787404484096. Its totient is φ = 2893140426000.
The previous prime is 4340132001013. The next prime is 4340132001059. The reversal of 4340132001033 is 3301002310434.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 4340132001033 - 217 = 4340131869961 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4340132000994 and 4340132001012.
It is not an unprimeable number, because it can be changed into a prime (4340132001013) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 70190953 + ... + 70252758.
It is an arithmetic number, because the mean of its divisors is an integer number (723425560512).
Almost surely, 24340132001033 is an apocalyptic number.
It is an amenable number.
4340132001033 is a deficient number, since it is larger than the sum of its proper divisors (1447272483063).
4340132001033 is a wasteful number, since it uses less digits than its factorization.
4340132001033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 140454015.
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 4340132001033 its reverse (3301002310434), we get a palindrome (7641134311467).
The spelling of 4340132001033 in words is "four trillion, three hundred forty billion, one hundred thirty-two million, one thousand, thirty-three".
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