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434013221203 = 1074056198329
BaseRepresentation
bin1100101000011010011…
…01000011000101010011
31112111021010110000220021
412110031031003011103
524102324341034303
6531214413324311
743233152340142
oct6241515030523
91474233400807
10434013221203
1115807816a971
1270146196697
1331c092a3933
1417013603759
15b452a09ebd
hex650d343153

434013221203 has 4 divisors (see below), whose sum is σ = 438069419640. Its totient is φ = 429957022768.

The previous prime is 434013221171. The next prime is 434013221207. The reversal of 434013221203 is 302122310434.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 434013221203 - 25 = 434013221171 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (434013221207) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2028099058 + ... + 2028099271.

It is an arithmetic number, because the mean of its divisors is an integer number (109517354910).

Almost surely, 2434013221203 is an apocalyptic number.

434013221203 is a deficient number, since it is larger than the sum of its proper divisors (4056198437).

434013221203 is a wasteful number, since it uses less digits than its factorization.

434013221203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4056198436.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 434013221203 its reverse (302122310434), we get a palindrome (736135531637).

The spelling of 434013221203 in words is "four hundred thirty-four billion, thirteen million, two hundred twenty-one thousand, two hundred three".

Divisors: 1 107 4056198329 434013221203