Base | Representation |
---|---|
bin | 110001010101111010110101… |
… | …0001101010001000111001001 |
3 | 2002220202000100112122121002010 |
4 | 1202223311222031101013021 |
5 | 423342000214134304140 |
6 | 4135030314000130133 |
7 | 160263663521521602 |
oct | 14253655215210711 |
9 | 2086660315577063 |
10 | 434021112025545 |
11 | 116324357916610 |
12 | 40818248306949 |
13 | 15824027661825 |
14 | 7926a3bba8da9 |
15 | 3529d4258c880 |
hex | 18abd6a3511c9 |
434021112025545 has 32 divisors (see below), whose sum is σ = 757565093222784. Its totient is φ = 210434208998400.
The previous prime is 434021112025507. The next prime is 434021112025561. The reversal of 434021112025545 is 545520211120434.
It is not a de Polignac number, because 434021112025545 - 239 = 433471356211657 is a prime.
It is a super-2 number, since 2×4340211120255452 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 201671889 + ... + 203812641.
It is an arithmetic number, because the mean of its divisors is an integer number (23673909163212).
Almost surely, 2434021112025545 is an apocalyptic number.
It is an amenable number.
434021112025545 is a deficient number, since it is larger than the sum of its proper divisors (323543981197239).
434021112025545 is a wasteful number, since it uses less digits than its factorization.
434021112025545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3369513.
The product of its (nonzero) digits is 192000, while the sum is 39.
Adding to 434021112025545 its reverse (545520211120434), we get a palindrome (979541323145979).
The spelling of 434021112025545 in words is "four hundred thirty-four trillion, twenty-one billion, one hundred twelve million, twenty-five thousand, five hundred forty-five".
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