Base | Representation |
---|---|
bin | 111111001010010100100… |
… | …111111101100011010001 |
3 | 120100221100200001102210202 |
4 | 333022110213331203101 |
5 | 1032103130040111112 |
6 | 13121542415504545 |
7 | 625404263166530 |
oct | 77122447754321 |
9 | 16327320042722 |
10 | 4340410472657 |
11 | 1423837615106 |
12 | 5a124a828155 |
13 | 2563b6a46c0c |
14 | 11011137c317 |
15 | 77d861d26c2 |
hex | 3f2949fd8d1 |
4340410472657 has 4 divisors (see below), whose sum is σ = 4960469111616. Its totient is φ = 3720351833700.
The previous prime is 4340410472641. The next prime is 4340410472659. The reversal of 4340410472657 is 7562740140434.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4340410472657 - 24 = 4340410472641 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4340410472659) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 310029319469 + ... + 310029319482.
It is an arithmetic number, because the mean of its divisors is an integer number (1240117277904).
Almost surely, 24340410472657 is an apocalyptic number.
It is an amenable number.
4340410472657 is a deficient number, since it is larger than the sum of its proper divisors (620058638959).
4340410472657 is an equidigital number, since it uses as much as digits as its factorization.
4340410472657 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 620058638958.
The product of its (nonzero) digits is 2257920, while the sum is 47.
The spelling of 4340410472657 in words is "four trillion, three hundred forty billion, four hundred ten million, four hundred seventy-two thousand, six hundred fifty-seven".
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