Base | Representation |
---|---|
bin | 10011101111011001011011… |
… | …10000011011100001100001 |
3 | 12200200221210200112120010020 |
4 | 21313230231300123201201 |
5 | 21142212141021143131 |
6 | 232154140224224053 |
7 | 12100161214650540 |
oct | 1167545560334141 |
9 | 180627720476106 |
10 | 43410002131041 |
11 | 12917095563247 |
12 | 4a51195a6b029 |
13 | 1b2b7129bb120 |
14 | aa10abad0157 |
15 | 5042d8ed8996 |
hex | 277b2dc1b861 |
43410002131041 has 16 divisors (see below), whose sum is σ = 71236926574464. Its totient is φ = 22897583541504.
The previous prime is 43410002131009. The next prime is 43410002131079. The reversal of 43410002131041 is 14013120001434.
It is not a de Polignac number, because 43410002131041 - 25 = 43410002131009 is a prime.
It is a super-2 number, since 2×434100021310412 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (43410002131081) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 79505498136 + ... + 79505498681.
It is an arithmetic number, because the mean of its divisors is an integer number (4452307910904).
Almost surely, 243410002131041 is an apocalyptic number.
It is an amenable number.
43410002131041 is a deficient number, since it is larger than the sum of its proper divisors (27826924443423).
43410002131041 is a wasteful number, since it uses less digits than its factorization.
43410002131041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 159010996840.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 43410002131041 its reverse (14013120001434), we get a palindrome (57423122132475).
The spelling of 43410002131041 in words is "forty-three trillion, four hundred ten billion, two million, one hundred thirty-one thousand, forty-one".
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