Base | Representation |
---|---|
bin | 111111001010111000100… |
… | …011101101111110001001 |
3 | 120100222220200110021101101 |
4 | 333022320203231332021 |
5 | 1032110343403340131 |
6 | 13122122313221401 |
7 | 625425233400430 |
oct | 77127043557611 |
9 | 16328820407341 |
10 | 4341013340041 |
11 | 1424016951314 |
12 | 5a1398701861 |
13 | 256481907991 |
14 | 11016b470117 |
15 | 77dbe0b9c61 |
hex | 3f2b88edf89 |
4341013340041 has 16 divisors (see below), whose sum is σ = 5005577401344. Its totient is φ = 3687560884224.
The previous prime is 4341013340009. The next prime is 4341013340087. The reversal of 4341013340041 is 1400433101434.
It is a happy number.
It is not a de Polignac number, because 4341013340041 - 25 = 4341013340009 is a prime.
It is a super-3 number, since 3×43410133400413 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4341013339991 and 4341013340009.
It is not an unprimeable number, because it can be changed into a prime (4341013340141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7543081 + ... + 8098153.
It is an arithmetic number, because the mean of its divisors is an integer number (312848587584).
Almost surely, 24341013340041 is an apocalyptic number.
It is an amenable number.
4341013340041 is a deficient number, since it is larger than the sum of its proper divisors (664564061303).
4341013340041 is a wasteful number, since it uses less digits than its factorization.
4341013340041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 565080.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 4341013340041 its reverse (1400433101434), we get a palindrome (5741446441475).
The spelling of 4341013340041 in words is "four trillion, three hundred forty-one billion, thirteen million, three hundred forty thousand, forty-one".
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