Base | Representation |
---|---|
bin | 111111001010111001000… |
… | …010011110001111110101 |
3 | 120100222221020121212110012 |
4 | 333022321002132033311 |
5 | 1032110402434331401 |
6 | 13122123202110005 |
7 | 625425362046116 |
oct | 77127102361765 |
9 | 16328836555405 |
10 | 4341021402101 |
11 | 142402045847a |
12 | 5a139b34b305 |
13 | 25648349b427 |
14 | 11016c56c20d |
15 | 77dbeb5d8bb |
hex | 3f2b909e3f5 |
4341021402101 has 4 divisors (see below), whose sum is σ = 4343180042304. Its totient is φ = 4338862761900.
The previous prime is 4341021402073. The next prime is 4341021402121. The reversal of 4341021402101 is 1012041201434.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4341021402101 - 26 = 4341021402037 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4341021402121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1079317085 + ... + 1079321106.
It is an arithmetic number, because the mean of its divisors is an integer number (1085795010576).
Almost surely, 24341021402101 is an apocalyptic number.
It is an amenable number.
4341021402101 is a deficient number, since it is larger than the sum of its proper divisors (2158640203).
4341021402101 is a wasteful number, since it uses less digits than its factorization.
4341021402101 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2158640202.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 4341021402101 its reverse (1012041201434), we get a palindrome (5353062603535).
The spelling of 4341021402101 in words is "four trillion, three hundred forty-one billion, twenty-one million, four hundred two thousand, one hundred one".
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