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4341112023121 = 67107605539409
BaseRepresentation
bin111111001010111110011…
…100001010100001010001
3120101000011120010220010021
4333022332130022201101
51032111044134214441
613122140200303441
7625430542236256
oct77127634124121
916330146126107
104341112023121
111424067623385
125a1405771b81
132564991a9c33
1411017a5db42d
1577dc7aae3d1
hex3f2be70a851

4341112023121 has 8 divisors (see below), whose sum is σ = 4447081427040. Its totient is φ = 4236353698368.

The previous prime is 4341112023077. The next prime is 4341112023151. The reversal of 4341112023121 is 1213202111434.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4341112023121 - 27 = 4341112022993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4341112023151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 302762536 + ... + 302776873.

It is an arithmetic number, because the mean of its divisors is an integer number (555885178380).

Almost surely, 24341112023121 is an apocalyptic number.

It is an amenable number.

4341112023121 is a deficient number, since it is larger than the sum of its proper divisors (105969403919).

4341112023121 is a wasteful number, since it uses less digits than its factorization.

4341112023121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 605539583.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 4341112023121 its reverse (1213202111434), we get a palindrome (5554314134555).

The spelling of 4341112023121 in words is "four trillion, three hundred forty-one billion, one hundred twelve million, twenty-three thousand, one hundred twenty-one".

Divisors: 1 67 107 7169 605539409 40571140403 64792716763 4341112023121