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4341133113 = 31447044371
BaseRepresentation
bin1000000101100000…
…00110111100111001
3102012112121102002220
410002300012330321
532342312224423
61554433314253
7212402010522
oct40260067471
912175542086
104341133113
111928502619
12a11a05989
135424c1a25
142d2793849
151a61ab9e3
hex102c06f39

4341133113 has 4 divisors (see below), whose sum is σ = 5788177488. Its totient is φ = 2894088740.

The previous prime is 4341133109. The next prime is 4341133133. The reversal of 4341133113 is 3113311434.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4341133113 - 22 = 4341133109 is a prime.

It is not an unprimeable number, because it can be changed into a prime (4341133133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 723522183 + ... + 723522188.

It is an arithmetic number, because the mean of its divisors is an integer number (1447044372).

Almost surely, 24341133113 is an apocalyptic number.

It is an amenable number.

4341133113 is a deficient number, since it is larger than the sum of its proper divisors (1447044375).

4341133113 is a wasteful number, since it uses less digits than its factorization.

4341133113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1447044374.

The product of its digits is 1296, while the sum is 24.

The square root of 4341133113 is about 65887.2758049686. The cubic root of 4341133113 is about 1631.3019962228.

Adding to 4341133113 its reverse (3113311434), we get a palindrome (7454444547).

The spelling of 4341133113 in words is "four billion, three hundred forty-one million, one hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 3 1447044371 4341133113