Base | Representation |
---|---|
bin | 111111001011001011000… |
… | …101100110101100001001 |
3 | 120101000201100102020220201 |
4 | 333023023011212230021 |
5 | 1032112012444304001 |
6 | 13122213220252201 |
7 | 625436026643536 |
oct | 77131305465411 |
9 | 16330640366821 |
10 | 4341324213001 |
11 | 1424166381816 |
12 | 5a1464841061 |
13 | 256501141789 |
14 | 11019a873d8d |
15 | 77ddb525501 |
hex | 3f2cb166b09 |
4341324213001 has 8 divisors (see below), whose sum is σ = 4388284802304. Its totient is φ = 4294456158720.
The previous prime is 4341324212947. The next prime is 4341324213011. The reversal of 4341324213001 is 1003124231434.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4341324213001 - 27 = 4341324212873 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4341324213011) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23039416 + ... + 23227081.
It is an arithmetic number, because the mean of its divisors is an integer number (548535600288).
Almost surely, 24341324213001 is an apocalyptic number.
It is an amenable number.
4341324213001 is a deficient number, since it is larger than the sum of its proper divisors (46960589303).
4341324213001 is a wasteful number, since it uses less digits than its factorization.
4341324213001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46267511.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 4341324213001 its reverse (1003124231434), we get a palindrome (5344448444435).
The spelling of 4341324213001 in words is "four trillion, three hundred forty-one billion, three hundred twenty-four million, two hundred thirteen thousand, one".
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