4341411140441 has 4 divisors (see below), whose sum is σ = 4491114972900. Its totient is φ = 4191707307984.

The previous prime is 4341411140387. The next prime is 4341411140447. The reversal of 4341411140441 is 1440411141434.

4341411140441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1909592334400 + 2431818806041 = 1381880^2 + 1559429^2 .

It is a cyclic number.

It is not a de Polignac number, because 4341411140441 - 2¹⁸ = 4341410878297 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4341411140398 and 4341411140407.

It is not an unprimeable number, because it can be changed into a prime (4341411140447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74851916186 + ... + 74851916243.

It is an arithmetic number, because the mean of its divisors is an integer number (1122778743225).

Almost surely, 2^{4341411140441} is an apocalyptic number.

It is an amenable number.

4341411140441 is a deficient number, since it is larger than the sum of its proper divisors (149703832459).

4341411140441 is a wasteful number, since it uses less digits than its factorization.

4341411140441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 149703832458.

The product of its (nonzero) digits is 12288, while the sum is 32.

Adding to 4341411140441 its reverse (1440411141434), we get a palindrome (5781822281875).

The spelling of 4341411140441 in words is "four trillion, three hundred forty-one billion, four hundred eleven million, one hundred forty thousand, four hundred forty-one".