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434142000103 = 762020285729
BaseRepresentation
bin1100101000101001110…
…00010011001111100111
31112111121002202200100011
412110110320103033213
524103110323000403
6531235253431051
743236305053630
oct6242470231747
91474532680304
10434142000103
11158133928409
127018133b487
1331c29b82676
1417026766887
15b45de96a6d
hex6514e133e7

434142000103 has 4 divisors (see below), whose sum is σ = 496162285840. Its totient is φ = 372121714368.

The previous prime is 434142000037. The next prime is 434142000169. The reversal of 434142000103 is 301000241434.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (434142000037) and next prime (434142000169).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-434142000103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (434142004103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31010142858 + ... + 31010142871.

It is an arithmetic number, because the mean of its divisors is an integer number (124040571460).

Almost surely, 2434142000103 is an apocalyptic number.

434142000103 is a deficient number, since it is larger than the sum of its proper divisors (62020285737).

434142000103 is an equidigital number, since it uses as much as digits as its factorization.

434142000103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62020285736.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 434142000103 its reverse (301000241434), we get a palindrome (735142241537).

The spelling of 434142000103 in words is "four hundred thirty-four billion, one hundred forty-two million, one hundred three", and thus it is an aban number.

Divisors: 1 7 62020285729 434142000103