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434151025213 = 2318876131531
BaseRepresentation
bin1100101000101010110…
…10101110101000111101
31112111121201202012110111
412110111122232220331
524103120130301323
6531240215110021
743236444553123
oct6242532565075
91474551665414
10434151025213
11158138a32084
1270184372311
1331c2b9c2579
1417027a35913
15b45eb7ac0d
hex65156aea3d

434151025213 has 4 divisors (see below), whose sum is σ = 453027156768. Its totient is φ = 415274893660.

The previous prime is 434151025207. The next prime is 434151025229. The reversal of 434151025213 is 312520151434.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 434151025213 - 217 = 434150894141 is a prime.

It is a super-2 number, since 2×4341510252132 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (434151025313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9438065743 + ... + 9438065788.

It is an arithmetic number, because the mean of its divisors is an integer number (113256789192).

Almost surely, 2434151025213 is an apocalyptic number.

It is an amenable number.

434151025213 is a deficient number, since it is larger than the sum of its proper divisors (18876131555).

434151025213 is a wasteful number, since it uses less digits than its factorization.

434151025213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18876131554.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 434151025213 its reverse (312520151434), we get a palindrome (746671176647).

The spelling of 434151025213 in words is "four hundred thirty-four billion, one hundred fifty-one million, twenty-five thousand, two hundred thirteen".

Divisors: 1 23 18876131531 434151025213